python poplib get headers from emails

Question

this is my actula code :

import poplib, sys, re, threading, time, Queue
from email import parser

    Mailbox = poplib.POP3(pop3, '110')
    Mailbox.user(username)
    Mailbox.pass_(password)
    numMessages = len(Mailbox.list()[1])
    for i in range(numMessages):
            fullemail = ''
            fullemail = '\n'.join([msg for msg in Mailbox.retr(i+1)[1]])
            msg = parser.Parser().parsestr(fullemail)
            for part in msg.walk():
                    print part.get_payload(decode=True)

print part.get_payload(decode=True) print body of email, how i can print header of email ?

You are not showing your imports but if you are using the Python `email` library, the currently second example on https://docs.python.org/3.4/library/email-examples.html shows you how. — tripleee, Dec 08 '17 at 11:07
Possible duplicate of [Extract just email headers in python](https://stackoverflow.com/questions/8424317/extract-just-email-headers-in-python) — tripleee, Dec 08 '17 at 11:07
If you think "the body" is well-defined, perhaps your understanding of email isn't yet very deep. — tripleee, Dec 08 '17 at 11:08

score 0 · Answer 1 · edited Sep 29 '18 at 10:32

0

the method items() of email.message.Message/email.message.EmailMessage object may be useful:

for t in msg.items():
    print(t)

t is a tuple like this (key,value).

edited Sep 29 '18 at 10:32

Vineeth Sai

3,389
7
23
34

answered Sep 29 '18 at 07:49

C.K.

1,409
10
20

python poplib get headers from emails

1 Answers1