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In Apiary, the cURL call to production by default is :

https://example.com/v1/findBrandCat?matchstring=&interestType=

I have to make a call in following structure:

https://example.com/v1/findBrandCat/matchstringVALUE/interestTypeVALUE

How to make it?

Subhashree R
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1 Answers1

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A URI template for the API resource can be defined as follows:

# GET /v1/findBrandCat/{matchstringValue}/{interestTypeValue}

+ Parameters
    + matchstringValue: (required, string)
    + interestTypeValue: (required, string)

+ Response 200 (application/json)
Oluwafemi Sule
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