Fetch value of selection field instead of key

Question

I defined a selection field in one model.

type = fields.Selection([('a','A'),('b','B'),('c','C')])

In one of function i tried to get string value instead of key.

@api.multi
    def testFunc(self):
    for res in self:
        print'Value',res.type //It prints 'a'.

I need to print 'A'.

How can i do this?

Charif DZ · Accepted Answer · 2017-11-30T04:56:54.210

4

Choose One of the solutions :

The most importing thing that you can get the selection list like this:

    self._fields['type'].selection

So try this:

    # convert the list to dictionary
    dict(self._fields['type'].selection).get(self.type)

IF you want the label to be translated in user language:

  # here the label return is translated.
  value = dict(self.fields['state']._description_selection(self.evn)).get(self.type)

edited Nov 30 '17 at 04:56

answered Nov 29 '17 at 14:42

Charif DZ

14,415
3
21
40

Hello Cherif. For odoo10 your solution not work for me. Please suggest me, how to solve this? – Pawan Kumar Sharma Apr 30 '18 at 11:09
Take a look at fields.py and see how to retrieve the value from there but what exactly didn't work what error did you have – Charif DZ Apr 30 '18 at 17:44

score 0 · Answer 2 · answered Jun 21 '19 at 19:41

0

You can use this method, it returns the string value, translated if it's the case:

@api.multi
    def testFunc(self):
    for res in self:
        print'Value', dict(res.fields_get(["type"],['selection'])['type']["selection"]).get(res.type)

answered Jun 21 '19 at 19:41

Beto

11
4

score 0 · Answer 3 · answered Apr 26 '21 at 02:43

0

A possible and simple solution would be:

VALUES_TYPE = [('a','A'),('b','B'),('c','C')]

type = fields.Selection(VALUES_TYPE )

dict(VALUES_TYPE )[self.type]

answered Apr 26 '21 at 02:43

Jorge Alberto Rueda Flores

175
8

Fetch value of selection field instead of key

3 Answers3