How to get a particular word/string in lua regex

Question

I have a problem to get a string. Here is my code:

conf = "option fn_o 'Operator'"
print(conf)
local s, e, pa = string.find(conf, "\b(?!option|fn_o)\b\w+")
print(s, e, pa)

I want to get an Operator only. In Javascript, that regex works good, but in Lua it doesn't. I think there is no problem because Lua is based on json so it is similar to javascript. Is there any problem?

Well, Lua has no regex support, it only has Lua patterns. Also, see http://lua-users.org/wiki/JsonModules — Wiktor Stribiżew, Nov 27 '17 at 11:53
I'll be frank, I'm a touch offended at that "Lua is based on JSON" comment. Javascript was partially inspired by Lua. — ATaco, Dec 04 '17 at 03:47

score 0 · Answer 1 · answered Nov 27 '17 at 12:43

Lua does not support full regular expressions out of the box, but there are libraries that do.

Lua includes patterns, which suffice for your task.

This code gets the string inside single quotes:

print(string.match(conf, "'(.-)'"))

The pattern reads: find a single quote and capture everything until the next single quote.

How to get a particular word/string in lua regex

1 Answers1