Adding two data types in bytearrayoutputstream and printing it

Question

I have used the following code. I just can't seem to get the value of x back from the byte array. Here is my code:

int seqNo = 0;
    ByteArrayOutputStream bout = new ByteArrayOutputStream();
    DataOutputStream out = new DataOutputStream(bout);
    try {
        out.writeInt(seqNo);
        String i = Integer.toString(seqNo) + "hello";
        byte[] b = i.getBytes();
        System.out.println(Arrays.toString(b));
        int x = b[0];
        System.out.println(x);
    } catch (IOException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }

Here is the output:

[48, 104, 101, 108, 108, 111]
48

The output should contain 0 instead of 48. Please help

[`String.getBytes()`](https://docs.oracle.com/javase/8/docs/api/java/lang/String.html#getBytes--) uses the user's default character encoding, which is not what you want except when it is exactly what want. Use one of the other `String.getBytes(xxxx)` with, say, `StandardCharsets.UTF-8`. — Tom Blodget, Nov 25 '17 at 21:09
Can you be sure the number is only one decimal digit? Is there some disadvantage to reversing each step? — Tom Blodget, Nov 25 '17 at 21:14

score 0 · Accepted Answer · answered Nov 25 '17 at 20:06

0

48 is the ASCII code of 0

 int x=b[0]-48;

answered Nov 25 '17 at 20:06

Mustapha Belmokhtar

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Adding two data types in bytearrayoutputstream and printing it

1 Answers1