Do you want something generic or something specific?
Specific is easy, this is the generic case:
const updateValExpr = r.expr(updateVal);
const updateStats = (stats, val) => val
.keys()
.map(key => r.branch(
stats.hasFields(key),
[key, stats(key).add(val(key))],
[key, val(key)]
))
.coerceTo('object')
r.table(...)
.update(stats =>
updateStats(stats.without('global'), updateValExpr.without('global'))
.merge({ global: updateStats(stats('global'), updateValExpr('global'))
)
There might be some bugs here sincce it's untested but the solution key point is the updateStats
function, the fact that you can get all the keys with .keys()
and that coerceTo('object')
transforms this array: [['a',1],['b',2]]
to this object: { a: 1, b: 2 }
,
Edit:
You can do it recursively, although with limited stack (since you can't send recursive stacks directly, they resolve when the query is actually built:
function updateStats(stats, val, stack = 10) {
return stack === 0
? {}
: val
.keys()
.map(key => r.branch(
stats.hasFields(key).not(),
[key, val(key)],
stats(key).typeOf().eq('OBJECT'),
[key, updateStats(stats(key), val(key), stack - 1)],
[key, stats(key).add(val(key))]
)).coerceTo('object')
}
r.table(...).update(row => updateStats(row, r(updateVal)).run(conn)
// test in admin panel
updateStats(r({
id: 1,
statistics: {
stat1: 1,
global: {
stat2: 3
},
stat111: 99
}
}), r({
statistics: {
stat1: 8,
global: {
stat2: 6
},
stat4: 3
}
}))