Assign a value to a parameter in application properties before use

Question

I have a property in my application.properties file in a SpringBoot project -

app.module.service.url=http://localhost:8090/{DOCID}

I have injected it into my Java file as below -

@Value("${app.module.service.url}")
private String url;

Now I need to replace DOCID with some value in my function(i.e-dynamic). How do I get to do this or am I completely missing it? I am aware that we can do this in case of message properties in Spring. But here I have nothing to do with Locales.

Edit:

There is some value which I need to put in place of {DOCID} when using it within my Java implementation.

...
public class Sample{

@Value("${app.module.service.url}")
private String url;

public void sampleFunc(){

String str = "random Value" //some dynamic value goes in here
...

Now I need to replace {DOCID} with str in url

Pramod S. Nikam · Answer 1 · 2017-11-15T08:30:47.943

1

Two way binding is not possible in Spring Properties.It can only read run time and environmental variables.

Please refer following link for more information.

https://github.com/spring-projects/spring-boot/wiki/Spring-Boot-Configuration-Binding

edited Nov 15 '17 at 08:30

answered Nov 15 '17 at 05:51

Pramod S. Nikam

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Actually, the config is part of `application.properties` already. I need to set the placeholder value in a function. Will update the question perhaps its not clear. – Rajeev Ranjan Nov 15 '17 at 06:30
@RajeevRanjan - Edited my my answer based on your edit. – Pramod S. Nikam Nov 15 '17 at 06:48
Actually @Pra Jazz, the fetching part need not be done during jar deployment. It is some value that is built up within the function which is stored in a variable `str`. Then it is to be put in place of `{DOCID}`. – Rajeev Ranjan Nov 15 '17 at 08:06

score 1 · Answer 2 · answered Jul 03 '21 at 08:36

You can use spring UriTemplate for this purpose.

In your implementation class:

...
public class Sample{

@Value("${app.module.service.url}")
private String url;

public void sampleFunc(){
 String dockId = someValue; // customize according to your need
 UriTemplate uriTemplate = new UriTemplate(url);
 URI uri = uriTemplate.expand(docId);
 new RestTemplate().postForEntity(uri, requestObhect, Responseclass.class);
}
...

For more information, you can refer : https://docs.spring.io/spring-framework/docs/current/javadoc-api/org/springframework/web/util/UriTemplate.html

score 0 · Answer 3 · edited Dec 21 '20 at 18:59

0

Try like this ...

app.module.service.url=http://localhost:8090/{{docId}}

And set run configuration as below

-DdocId = 133323 // any number which you want

edited Dec 21 '20 at 18:59

myeongkil kim

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answered Dec 21 '20 at 06:15

user14863296

1

Is it possible to write more about `And set run configuration as below`? also, can you attach the actual test results? – myeongkil kim Dec 21 '20 at 06:40

Assign a value to a parameter in application properties before use

3 Answers3