UnicodeEncodeError in python3.4.2?

Question

Hi i have the following code in python3.4.2:

s='416f1c7918f83a4f1922d86df5e78348'; w="0123456789abcdef"; x=''.join([chr(w.index(s[i])*16+w.index(s[i+1])) if(i%2==0) else '' for i in range(len(s))]); print(x);

and it shows this error
UnicodeEncodeError: 'ascii' codec can't encode character '\xf8' in position 5: ordinal not in range (128)

Why is this happening ? isn't chr in python3 supposed to take more than 128 ?

score 0 · Accepted Answer · answered Nov 09 '17 at 01:26

0

Too much work.

>>> binascii.unhexlify(s)
b'Ao\x1cy\x18\xf8:O\x19"\xd8m\xf5\xe7\x83H'

answered Nov 09 '17 at 01:26

Ignacio Vazquez-Abrams

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not even the question ... , if you want to decode(encoding) it shows the same error . – Sumanto Dinar Nov 09 '17 at 01:39
The problem is that `chr()` is for characters, but you don't have characters. – Ignacio Vazquez-Abrams Nov 09 '17 at 01:40
can you elaborate more? I don't understand "you don't have characters" ... – Sumanto Dinar Nov 09 '17 at 01:41
You have bytes. The difference matters now that you're using 3.x. – Ignacio Vazquez-Abrams Nov 09 '17 at 01:42
so what should i do then? – Sumanto Dinar Nov 09 '17 at 01:42
Stop using `chr()` and start using bytes. Or do it the right way in the first place. – Ignacio Vazquez-Abrams Nov 09 '17 at 01:43
And? Decode it using the appropriate charset once you've converted it. – Ignacio Vazquez-Abrams Nov 09 '17 at 01:45

UnicodeEncodeError in python3.4.2?

1 Answers1