combine two serialize data in php

Question

$var1='a:1:{i:123;s:3:"123";}';

$var2='a:1:{i:56;s:2:"56";}';

output a:2:{i:56;s:2:"56";i:123;s:3:"123";}

Without changing the value of i

Example2;

$var1='a:2:{i:56;s:2:"56";i:123;s:3:"123";}';

$var2='a:1:{i:154;s:3:"154";}';

ouput a:3:{i:56;s:2:"56";i:123;s:3:"123";i:154;s:3:"154";}

i am using

$a=unserialize($var1); 
$a2=unserialize($var2); 
$result = array_merge($a, $a2); 
$serialized_array=serialize($result); 
print_r($serialized_array);

but all the values of i got changed

also what does s stands for in above strings

Unserialize them, combine them however you want, then serialize that. — Barmar, Nov 07 '17 at 17:43
Are you asking how to do this? If so, why are you judging anything by its serialized output, rather than just specifying the array you want. — iainn, Nov 07 '17 at 17:44
See https://stackoverflow.com/questions/14297926/structure-of-a-serialized-php-string to understand the parts of a serialized string. — Barmar, Nov 07 '17 at 17:45
@Barmar They're right aren't they? Arrays are serialized as `a:count:{key;value}` — iainn, Nov 07 '17 at 17:49
@Barmar can you please provide me the code how to do that, i am using $a=unserialize($var1); $a2=unserialize($var2); $result = array_merge($a, $a2); $serialized_array=serialize($result); print_r($serialized_array); but all the values of i got changed — Nitesh kumar, Nov 07 '17 at 17:52

Barmar · Answer 1 · 2017-11-07T18:02:46.640

2

Unserialize them, concatenate the arrays, then serialize that.

echo serialize(unserialize($var1) + unserialize($var2));

You have to use + instead of array_merge() because the latter re-indexes the array if the keys are all integers. Since all your keys begin with i:, that means they're numeric indexes.

DEMO

For the meaning of s, see Structure of a Serialized PHP string

edited Nov 07 '17 at 18:02

answered Nov 07 '17 at 17:51

Barmar

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a:2:{i:0;s:3:"123";i:1;s:2:"56";} as you can see the i:0 and i:1 but is should be same like a:2:{i:123;s:3:"123";i:56;s:2:"56";} (i:123 and i:56) – Nitesh kumar Nov 07 '17 at 17:58
`array_merge` reindexes the arrays if the keys are numbers rather than strings. That's why we use `+` in the answers. – Barmar Nov 07 '17 at 18:00
one last thing please help $var1='a:1:{i:4;i:4;}'; $var2='a:1:{i:3;s:1:"3";}'; output = a:2:{i:3;s:1:"3"; i:4;s:1:"4";} as you can see it add s:1 to $var1. how can i do that – – Nitesh kumar Nov 07 '17 at 18:17
$tournament_candidate='a:1:{i:4;i:4;}' and $tournament_competitors='a:1:{i:3;s:1:"3";}'; after union it should be like this a:2:{i:3;s:1:"3"; i:4;s:1:"4";} – Nitesh kumar Nov 07 '17 at 18:23
Why is the value a number instead of a string in the first array? – Barmar Nov 07 '17 at 18:24
After unserializing, you can use a `foreach` loop to replace numbers with strings. – Barmar Nov 07 '17 at 18:25
But most of the time PHP doesn't care, it will automatically convert between numbers and strings as needed. – Barmar Nov 07 '17 at 18:25
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Stop thinking in terms of serialized data, and work with the original arrays. – Barmar Nov 07 '17 at 18:26
Thank you for this! – Karra Max Nov 06 '20 at 23:32

score 0 · Answer 2 · answered Nov 07 '17 at 17:56

0

Using array_merge will re-index arrays with numeric keys. If you want to avoid this, you can use the array union operator (+) instead:

$combined = unserialize($var2) + unserialize($var1);

This will give you the correct serialized output.

See https://eval.in/894864 to demonstrate the difference.

answered Nov 07 '17 at 17:56

iainn

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one last thing please help $var1='a:1:{i:4;i:4;}'; $var2='a:1:{i:3;s:1:"3";}'; output = a:2:{i:3;s:1:"3"; i:4;s:1:"4";} as you can see it add s:1 to $var1. how can i do that – Nitesh kumar Nov 07 '17 at 18:17

combine two serialize data in php

2 Answers2