Avoid debug and callstack for a piece of code in c#

Question

In Delphi the compiler directives {$d-} and {$l-} allow you to effectively avoid generation of debug and local variable information for a defined section of code.

In a practical matter that has the effect to "hide" the code from the debug view, it doesn't appear in the call stack and you don't step into it while debugging.

Is there any way to achieve the same result in c# using VS 2008?

Note: The reason is we have a stable framework which does not need to be debugged but tend to mess up with the call stack and with the standard debug flow.

csharptest.net · Accepted Answer · 2011-01-17T17:37:31.720

6

I use DebuggerNonUserCodeAttribute so that you by default do not break or step into the code; However, the benifit to this over DebuggerStepThrough is that you can go to the Options->Debugger->Just My Code setting and allow breaking/debugging of the code you marked. This helps significantly if you have issues. I typically use it on entire classes.

BTW, the call stack will automatically hide non-user code as marked with this attribute :) Of course you can simply right-click the call stack window and toggle "Show External Code" to hide/show the missing stack information.

edited Jan 17 '11 at 17:37

answered Jan 17 '11 at 16:59

csharptest.net

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I was just going to say that. Beat me to it. – Patrick Jan 17 '11 at 17:03
Ok, this seems to do both but I can't check it until tomorrow so I'll access the answer then :) – Jorge Córdoba Jan 17 '11 at 17:37

BrokenGlass · Answer 2 · 2011-01-17T16:59:25.237

3

I think you want the DebuggerStepThrough attribute:

DebuggerStepThrough instructs the debugger to step through the code instead of stepping into the code.

[DebuggerStepThrough]
public void MyMethod()
{

}

This is especially useful for setters/getters since debugging into those usually just adds noise (example from msdn):

public int Quantity
{ 
    [DebuggerStepThrough] 
    get { return ComplexLogicConvertedToMethod(); } 
    [DebuggerStepThrough]      
    set { this.quantity = value ; }
}

edited Jan 17 '11 at 16:59

answered Jan 17 '11 at 16:52

BrokenGlass

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Cool, very useful. Did not know about this one. – detunized Jan 17 '11 at 16:54
Cool, but would that get rid of the callstack entries as well?? – Jorge Córdoba Jan 17 '11 at 17:33

score 0 · Answer 3 · answered Jan 17 '11 at 17:02

0

Or to skip a specific section of the code:

... some production code
#if DEBUG
    Console.WriteLine("Debug version");
#endif
... some more production code

answered Jan 17 '11 at 17:02

Mark Robinson

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Avoid debug and callstack for a piece of code in c#

3 Answers3