palindrome or not practice program using user input

Question

def reverse(string):
    return string[::-1]
def isPalindrome(string):
    temp=reverse(string)
    if temp==string:
        return True
    else:
        return False

string='tanmay' # input('enter a word')
ans=isPalindrome(string)
if ans==1:
    print' Yes palindrome'
else:
    print' no its not a palindrome'

if I ask for an input from the user the error what I got was Traceback (most recent call last):

File "C:/Python27/prac06-2.py", line 10, in <module>
    string=input('enter a word')
  File "<string>", line 1, in <module>

NameError: name 'tanmay' is not defined

but when I enter a string by myself the program is executed successfully

You should first make sure that the code you post here is the same as the code you run. Judging by your error messages, it isn't. `False` with an upper `F` is what you should be using. — cs95, Nov 06 '17 at 15:49

ktzr · Answer 1 · 2018-05-11T00:08:31.510

in python 2.7 input() evaluates the given input, you should use raw_input() to read in the data as a string. On another note, temp==string evaluates to a boolean so you do not need to put it in an if statement you can simply return temp==string

def reverse(string):
    return string[::-1]
def isPalindrome(string):
    temp=reverse(string)
    return temp==string

string=raw_input('enter a word')
if isPalindrome(string):
    print(' Yes palindrome')
else:
    print(' no its not a palindrome')

You can simplify isPalindrome() further by removing reverse() to:

def isPalindrome(string):
    return string == string[::-1]

score 0 · Answer 2 · answered Nov 06 '17 at 15:50

You are returning a boolean True or False and you are trying to compare the result with a value 1. Here is how you should invoke it.

ans = isPalindrome(string)
if ans: # you can also do (if ans == True)
    print 'Yes, it is a palindrome'
else:
    print 'No, it is not a palindrome'

palindrome or not practice program using user input

2 Answers2