Xtext standalone and validation

Question

Building a standalone program parsing a file, I used the first option of http://www.davehofmann.de/?p=101

A validation is defined that give an error (red under line in eclipse) if text does not start with a capital letter.

The standalone parser does not give an error of an input file that does not pass the validation. How can I ask the standalone implementation also the verify the validations?

Update 1

The classed used to parse the grammar with checkResource included:

class XtextParser {
    @Inject
    private IParser parser;
    new() {
        var injector = new MyDslStandaloneSetup().
                          createInjectorAndDoEMFRegistration();
        injector.injectMembers(this)
    }
    def EObject parse(Reader reader) throws IOException {
        var result = parser.parse(reader)
        if (result.hasSyntaxErrors()) {
            throw new ParseException("Provided input contains syntax errors.")
        }
        var resource = result.getRootASTElement().eResource() 
        //resource is null
        //checkResource(resource)
        return result.getRootASTElement();
    }
    @Inject IResourceValidator resourceValidator

    def void checkResource(Resource resource) {
        val issues = resourceValidator.validate(resource, 
                                 CheckMode.ALL, CancelIndicator.NullImpl)
        for (issue : issues) {
            switch issue.severity {
                case ERROR:
                    println("ERROR: " + issue.message)
                case WARNING:
                    println("WARNING: " + issue.message)
            }
        }
    }
}

Christian Dietrich · Accepted Answer · 2017-11-05T08:06:52.337

5

if you dont call the validator it wont validate. so call it (pseudo code)

@Inject IResourceValidator resourceValidator

def void checkResource(Resource resource) {
    val issues = resourceValidator.validate(resource,
            CheckMode.ALL, CancelIndicator.NullImpl)
    for (issue: issues) {
        switch issue.severity {
            case ERROR:
                println("ERROR: " + issue.message)
            case WARNING:
                println("WARNING: " + issue.message)
        }
    }
}

since the blog you posted is very vague on how to call

import java.io.IOException;
import java.util.List;

import org.eclipse.emf.common.util.URI;
import org.eclipse.emf.ecore.resource.Resource;
import org.eclipse.emf.ecore.resource.ResourceSet;
import org.eclipse.xtext.util.CancelIndicator;
import org.eclipse.xtext.validation.CheckMode;
import org.eclipse.xtext.validation.IResourceValidator;
import org.eclipse.xtext.validation.Issue;

import com.google.inject.Injector;

public class Main {

    public static void main(String[] args) throws IOException {
        Injector injector = new MyDslStandaloneSetup().createInjectorAndDoEMFRegistration();
        ResourceSet rs = injector.getInstance(ResourceSet.class);
        Resource resource = rs.getResource(URI.createURI("test.mydsl"), true);
        resource.load(null);
        IResourceValidator validator = injector.getInstance(IResourceValidator.class);
        List<Issue> issues = validator.validate(resource,
                CheckMode.ALL, CancelIndicator.NullImpl);
        for (Issue issue: issues) {
            switch (issue.getSeverity()) {
                case ERROR:
                    System.out.println("ERROR: " + issue.getMessage());
                case WARNING:
                        System.out.println("WARNING: " + issue.getMessage());
            }
        }
    }

}

edited Nov 05 '17 at 08:06

answered Nov 04 '17 at 16:46

Christian Dietrich

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How do I convert object of type IParserResults to type Resource? – Johan Nov 04 '17 at 22:24
Parse result gives you root ast element gives you eResource – Christian Dietrich Nov 04 '17 at 22:26
The object returned by `result.getRootASTElement().eResource()` is null – Johan Nov 05 '17 at 07:51
the share your complete grammar, example model and code. i cannot read your mind – Christian Dietrich Nov 05 '17 at 07:58
and yes the code you shared has no resource cause it is bad code – Christian Dietrich Nov 05 '17 at 08:00
1

updated my answer with the "default" way how not to call IParser. nobody wants to call IParser directly. why do you want? – Christian Dietrich Nov 05 '17 at 08:07
I need a jar file that accepts a file name what must he parsed according to the grammar. Currently use the Hallo xtext example as a grammar. – Johan Nov 05 '17 at 15:54
1

Simply ask injector for IGenerator2 javaiofilesystemaccess and call the generator – Christian Dietrich Nov 10 '18 at 19:42
What is the proper way to create an instance of IFileSystemAccess2? – Johan Nov 10 '18 at 19:59
1

Ask injector for javaiofilesystemaccess – Christian Dietrich Nov 10 '18 at 20:00

Xtext standalone and validation

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