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I m trying to get an instance of NSParagraphStyle.default.mutableCopy() but are we sure that mutableCopy() will always contain a value?

var paragraphStyle = NSParagraphStyle.default.mutableCopy() as! NSMutableParagraphStyle

Would it possible to do this without force unwraping?

raed
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1 Answers1

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Yes, it's much simpler:

let paragraphStyle = NSMutableParagraphStyle() // Note the `let`

You get the default parameters with the default initializer.

Apart from that in this case you can be sure that mutableCopy() will always contain a value because NSParagraphStyle clearly conforms to NSCopying.

vadian
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