Extracting .zip in python

Question

I got BadZipfile: Bad magic number for file header error while extracting a .zip using python2 zipfile.ZipFile

Same .zip when extracted with unzip gives file #1: bad zipfile offset (local header sig): 0 but gets extracted with exit code 2.

When using jar -xf file.zip the command completes with $? == 0 with nothing being extracted.

Using file gives:

file -i file.zip
file.zip application/octet-stream; charset=binary

This gives incorrect header for zipfile

$ hexdump -C file.zip | head -10
00000000  50 67 f0 de 1e 7a 29 e4  93 56 3f 11 a2 5f b6 97  |Pg...z)..V?.._..|

Correct header is:

00000000  50 4b 03 04 14 00 08 08  08 00 28 3e 4b 4b 00 00  |PK........(>KK..|

Why is the file listed as application/octet-stream ?

I am on

Distributor ID: Ubuntu
Description:    Ubuntu 14.04.5 LTS
Release:    14.04
Codename:   trusty

Whats going on ? What file format is this ? Any pointers ?

Possible duplicate of [Bad magic number error with ZipFile module in Python](https://stackoverflow.com/questions/7703639/bad-magic-number-error-with-zipfile-module-in-python) — Elis Byberi, Oct 28 '17 at 21:22
@RomanPerekhrest With unzip I get exit code 2 but the file gets extracted. — Ankur Agarwal, Oct 28 '17 at 21:36
I added few extra details from hexdump. Which file format is this ? — Ankur Agarwal, Oct 28 '17 at 22:17

score 1 · Answer 1 · answered Oct 28 '17 at 21:40

1

Have you tried this?

import zipfile
zip_ref = zipfile.ZipFile(path_to_zip_file, 'r')
zip_ref.extractall(directory_to_extract_to)
zip_ref.close()

answered Oct 28 '17 at 21:40

Josef B.

Then may be this could help [https://www.programcreek.com/python/example/3149/zipfile.BadZipfile] – Josef B. Oct 28 '17 at 22:01

1 Answers1