Which will be loaded first static block or static variable?

Question

As i read every one is saying static block will be executed first but when i run a piece of code i found that static variable is loading first.Now this is confusing me please give a proper explanation.

Code

public class MyClass 
{
    static int x=show();
    static
    {
        System.out.println("Hello Mayar");
    }
    public static int show()
    {
        System.out.println("Hello Show");
        return 1;
    }
    public static void main(String a[])
    {
        System.out.println("Hello Main");
    }
}

Output

Hello Show
Hello Mayar
Hello Main

*where* did you read that statement / claim? – luk2302 Oct 24 '17 at 08:43 — luk2302, Oct 24 '17 at 08:43

diginoise · Answer 1 · 2017-10-24T08:55:03.770

7

Static blocks and variables are evaluated in their order of appearance within the java source file.

As per Java 8 spec on class initialization:

Next, execute either the class variable initializers and static initializers of the class, or the field initializers of the interface, in textual order, as though they were a single block.

edited Oct 24 '17 at 08:55

answered Oct 24 '17 at 08:44

diginoise

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Don't answer such [obvious duplicates](https://stackoverflow.com/q/15427747/476716). – OrangeDog Oct 24 '17 at 08:52
apologies @OrangeDog ! – diginoise Oct 24 '17 at 09:00

Which will be loaded first static block or static variable?

Code

Output

1 Answers1

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