get source code for method with @property decorator python

Question

Suppose I have a class MyClass that has a property created with the @property decorator, like this:

class MyClass(object):
    @property
    def foo(self):
        if whatever:
            return True
        else:
            return False

Suppose I want to use the python inspect module to get the source code that defines the property. I know how to do this for methods (inspect.getsource) but I don't know how to do this for property objects. Anyone know how to do this?

Huh. I'm surprised `inspect.getsource` doesn't handle that automatically. — user2357112, Oct 23 '17 at 20:28

score 8 · Accepted Answer · answered Oct 23 '17 at 20:29

8

Access the underlying getter function through the property's fget attribute:

print(inspect.getsource(MyClass.foo.fget))

If it has a setter or deleter, you can access those through fset and fdel:

print(inspect.getsource(MyClass.foo.fset))
print(inspect.getsource(MyClass.foo.fdel))

answered Oct 23 '17 at 20:29

user2357112

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awesome! Just what I needed! – Marc Oct 23 '17 at 21:20

get source code for method with @property decorator python

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