Can the scope resolution operator be used in the definition of a member function when the member function is defined outside of its class definition? Like this:
class Myclass{
private:
void foo();
public:
void foo2();
};
void Myclass::foo()
{
// do stuff. . .
}
My teacher gave us notes that demonstrate the use of the scope resolution operator only for member functions that are public. Can anyone clear this up?
