Jackson deserialization - dealing with generated values with no fields

Question

I have a simple class:

@JsonIdentityInfo(generator = ObjectIdGenerators.PropertyGenerator.class, property = "id", scope = Endpoint.class)
public class Endpoint {

    @Id
    @GeneratedValue(strategy = GenerationType.AUTO)
    @JsonView({View.Endpoint.class, View.User.class})
    private Long id;

    @NotNull
    @NotEmpty(message = "Phone number is required.")
    @JsonView({View.Endpoint.class, View.Call.class, View.User.class})
    private String phoneNumber;

    @JsonView({View.Endpoint.class, View.Call.class, View.User.class})
    private String callerId;

    @ManyToOne(optional = false)
    @JsonView(View.Endpoint.class)
    @ApiModelProperty(hidden = true)
    private User user;

    ...

    @Override
    @JsonView({View.Endpoint.class, View.Call.class, View.User.class})
    public String getUri() {
        return EndpointController.BASE_PATH + "/" + getId();
    }

}

I get the following error when trying to deserialize:

com.fasterxml.jackson.databind.exc.UnrecognizedPropertyException: Unrecognized field "uri" (class com.example.server.telephony.endpoint.Endpoint), not marked as ignorable (5 known properties: "id", "label", "callerId", "phoneNumber", "user"])

Since URI is a generated value there is no field to annotate with @JsonIgnore. Any suggestions on what to do in this case?

You could consider [mix-ins](https://stackoverflow.com/a/38889775/1426227). — cassiomolin, Oct 11 '17 at 13:36
when you are using @JsonIdentityInfo what is requirement to have @JsonView?! — Ali Akbarpour, Oct 11 '17 at 15:32
@Generic I use `@JsonView` to avoid loops when I parse the `User` or `Endpoint` class which have a one to many relationship. Added these at different times so haven't evaluated if I need both. Does the use of `@JsonIdentityInfo` handle circular references? — Leon Roy, Oct 11 '17 at 17:33

score 1 · Answer 1 · answered Oct 15 '17 at 04:56

Annotate your Endpoint class using @JsonIgnoreProperties(ignoreUnknown = true)

Or configure the ObjectMapper with the following option to affect all POJOs deserialized with this Mapper:

objectMapper.configure(DeserializationFeature.FAIL_ON_UNKNOWN_PROPERTIES, false);

Jackson deserialization - dealing with generated values with no fields

1 Answers1