How to redirect user to random part of url and this url should match jsp page?

Question

I use servlets 3 and jsp and this is configuration question.

In servlet for url 'mydomain.com/builder/', I have to generate random ID and append it to my current url, like:

'mydomain.com/builder/randomID0'

Next, I want to redirect user to this url. So I need to match this new url to existent jsp page.

How to do this in servlet 3?

score 0 · Answer 1 · answered Oct 07 '17 at 18:05

0

You should get the current url as a String object via the getRequestURI() method of the HTTPServletRequest class, then generate the randomID String object and concatenate one another into a newUrl String.

Then use sendRedirect(newUrl) of the HTTPServletResponse class in order to let the user navigate to that new url.

answered Oct 07 '17 at 18:05

Emanuele Giona

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Thanks for response. I want to send user jsp file but rewrite url – Jay Smith Oct 07 '17 at 18:14
Don'r redirect to another url but only rewrite url – Jay Smith Oct 07 '17 at 18:14
In this case, you would need to use a sendRedirect in order to rewrite the url for the client, then make it process into a servlet and use the `forward()` method of `RequestDispatcher` class in order to send the client the wanted JSP file while still keeping the old url (if I understood what you want to do) – Emanuele Giona Oct 08 '17 at 17:26
Can I change url in filter after httpservlet ? – Jay Smith Oct 09 '17 at 16:45
What do you mean for filter? Is it the browser's address bar? – Emanuele Giona Oct 09 '17 at 17:49
Actually I am looking for a way to redirect from `/pc-builder/` to `/pc-builder/` and don't harm SEO rank of `/pc-builder/` page. – Jay Smith Oct 10 '17 at 06:52

How to redirect user to random part of url and this url should match jsp page?

1 Answers1