why does Pow function return unexpected values..?

Question

#include <stdio.h>
#include <iostream>
#include <math.h>
using namespace std;
int main()
{
    int i;
    i = 2;
    printf("%d %d %d\n", i,pow(i,2),pow(i,3));
    return 0;
}

/* I expect the output to be 2,4,8.But the output shown is 2 0 1074790400.Can anyone explain me the reason please..? */

pow is double , so u need %f – roshan_nazareth Oct 03 '17 at 11:01 — roshan_nazareth, Oct 03 '17 at 11:01

Bathsheba · Answer 1 · 2017-10-03T11:06:20.893

5

The return type of the overload of pow that you're using is double, so the behaviour of your code is undefined due to the invalid printf format specifiers.

Reference: http://en.cppreference.com/w/cpp/numeric/math/pow

edited Oct 03 '17 at 11:06

answered Oct 03 '17 at 10:56

Bathsheba

231,907
34
361
483

Consider using std::cout. You do not habe to care about the type you Luke to output. – schorsch312 Oct 03 '17 at 12:27

why does Pow function return unexpected values..?

1 Answers1