Split text contains number to list of string

Question

I have numbers and to want to split it to list of string using special character on it and with out removing special character on it like split

1,245.00
to
1
,
245
.
00

Hint: [`Character.isDigit()`](https://docs.oracle.com/javase/8/docs/api/java/lang/Character.html#isDigit-char-) — jmj, Oct 03 '17 at 06:39
@4castle Nice answer, but perhaps if the OP would want to split at certain types of non word boundary characters then this might not work as planned. — Tim Biegeleisen, Oct 03 '17 at 06:47
Refer this question, https://stackoverflow.com/questions/4416425/how-to-split-string-with-some-separator-but-without-removing-that-separator-in-j — Krishnan, Oct 03 '17 at 06:47

score 1 · Accepted Answer · answered Oct 03 '17 at 06:42

Split your string using lookaheads:

String input = "1,245.00";
String[] parts = input.split("(?=[^A-Za-z0-9])|(?<=[^A-Za-z0-9])");
for(String part : parts) {
    System.out.println(part);
}

This splits if, at any position is the string, either the preceding or proceeding character be a non letter or number.

Output:

Demo here:

Rextester

gil.fernandes · Answer 2 · 2017-10-03T08:26:51.903

There are multiple options available. You can use the boundary (credits to @4castle), but also lookahead (credits to the previous reply) and lookbehind.

Here are three options which all work:

String input = "1,245.00";
// look-ahead only
Stream.of(input.split("(?=[,.])|(?<=[^\\d])")).forEach(System.out::println);
System.out.println();
// Boundary
Stream.of(input.split("\\b")).forEach(System.out::println);
System.out.println();
// Mix of look-behind and look-ahead
Stream.of(input.split("(?![\\d])|(?<=[^\\d])")).forEach(System.out::println);

All print together:

Split text contains number to list of string

2 Answers2

Rextester