Why does 1 == int evaluates to False?

Question

Why does this print False in Python 3?

>>> 1 == int
False

Because you're comparing two objects that one of that has the value of 1 and other one doesn't have a value at all. `int` is actually a type object. It denotes a type in python and `1` is an `int` type object. — Mazdak, Sep 27 '17 at 11:03
Of course `int` has a value; it's just not an *integer* value, but a type value. — chepner, Sep 27 '17 at 11:42

score 4 · Accepted Answer · answered Sep 27 '17 at 11:03

4

Because that isn't at all doing what you think it is. You are comparing the integer value 1 with the type int; naturally they are not equal.

If you want to check whether an object is of a certain type, use isinstance:

isinstance(1, int)

answered Sep 27 '17 at 11:03

Daniel Roseman

Alperen · Answer 2 · 2017-09-27T12:22:30.247

0

I guess, what you want to use is this:

>>> type(1) is int
True

or

>>> type(1) == int
True

edited Sep 27 '17 at 12:22

answered Sep 27 '17 at 11:04

Alperen

2 Answers2