PI decimal using Math.Round

Question

I'm looking for an answer to the following:

Round the mathematical constant pi to 2 or 4 decimals.

I have tried the following:

Double piRounded;
piRounded = Math.Round.PI(4);
piRounded = Math.Round.PI(2);

This results in the following error:

'System.Math.Round(double)' is a 'method', which is not valid in the given context

Copy/paste you code directy in the post, do not upload a picture — Bidou, Sep 25 '17 at 18:47
You have red squiggles under the `Round` method call. What does that error tell you? ( — Rufus L, Sep 25 '17 at 18:49

score 0 · Accepted Answer · answered Sep 25 '17 at 18:50

0

Math.Round in your code is being specified as a property, not a method invocation.

Place your parameters in the round function like Math.Round(...) - You will want to pass in the PI constant.

Math.Round(Math.PI, 4) (as stated in comments).

answered Sep 25 '17 at 18:50

Miek

score 0 · Answer 2 · answered Sep 25 '17 at 18:53

0

Use:

Math.Round(Math.PI, 2);

and

Math.Round(Math.PI, 4);

respectively

answered Sep 25 '17 at 18:53

Thank you! i got it, sorry if i did some things wrong in the forum like the screenshot... Have a nice day! – Pieter Pauwels Sep 25 '17 at 18:55
Please mark as good answer =) – Santiago San Martin Sep 25 '17 at 18:56

2 Answers2