Can I get the iterator / iterated variable from xargs?

Question

./script1 | xargs -L1 ./script2 {}

script1 gives me lines of output, I want to pass each line of output into script2.

Right now, it's running script2 without any parameters.

How do I give script2 the values of each line that xargs gets?. I thought {} was that variable.

When I remove `{}` it runs as if script2 has no output. – Khadijah Celestine Sep 25 '17 at 16:15 — Khadijah Celestine, Sep 25 '17 at 16:15

Kaushik Nayak · Answer 1 · 2017-09-25T15:51:30.793

1

Use -I option of xargs to pass each line of output into script2 separately as in

./script2 <line1> ./script2 <line2> ./script2 <line3>

./script1 | xargs -I {} ./script2 {}

Remove {} from your script to pass each line of output into script2 together as in - ./script2 <line1> <line2> <line3>

./script1 | xargs -L1 ./script2

edited Sep 25 '17 at 15:51

answered Sep 25 '17 at 15:31

Kaushik Nayak

`./script1 | xargs -I {} ./script2 {}` when I do this it runs script2 as if it had no output, but it runs it x times, where x is the number of lines in script 1. – Khadijah Celestine Sep 25 '17 at 16:12
`./script2 ./script2 ./script2 ` You're right, this is the behavior I want. – Khadijah Celestine Sep 25 '17 at 16:14
Ok. Isn't it working for you?, coz it works fine when I tested with my sample script. – Kaushik Nayak Sep 25 '17 at 16:40

1 Answers1