return all the indices where element is present in a python list

Question

This return only the first index value where the char is present in the list. I need all the indices where char is present.

  def find_loc(char):
    for sub_list in chunks:
        if char in sub_list:
                return chunks.index(sub_list), sub_list.index(char)

Flagging for "Very low quality". Have a look at ["How do I ask a good question?"](https://stackoverflow.com/help/how-to-ask) — Paco H., Sep 20 '17 at 11:36
Possible duplicate of [How to find all occurrences of an element in a list?](https://stackoverflow.com/questions/6294179/how-to-find-all-occurrences-of-an-element-in-a-list) — Chris_Rands, Sep 20 '17 at 11:41

score 0 · Answer 1 · answered Sep 20 '17 at 11:37

0

Index method returns the first index value encountered.

Help on method_descriptor:

index(...)
    L.index(value, [start, [stop]]) -> integer -- return first index of value.
    Raises ValueError if the value is not present.

answered Sep 20 '17 at 11:37

bhansa

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is there any method by which i can get all the index values, – shivam singhal Sep 20 '17 at 11:39
use [`enumerate`](http://book.pythontips.com/en/latest/enumerate.html) and put a condition. – bhansa Sep 20 '17 at 11:40
@shivamsinghal check the above link for enumerate. – bhansa Sep 20 '17 at 16:38

score 0 · Answer 2 · answered Sep 20 '17 at 12:07

0

Use this snippet:

def indexes(iterable, obj):
    encounters = []
    for i in range(len(iterable)):
        if iterable[i] == obj:
            encounters.append(i)
    return encounters

answered Sep 20 '17 at 12:07

Kotauskas

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return all the indices where element is present in a python list

2 Answers2