Node - How to catch split() error?

Question

I have a question about NodeJs. Since 6.6 it say when unhandled promise can't be fetched.

To avoid that, I red I need to catch the error, but... If I got that, how should I proceed?

args[1] = args[1].split('!')[1].split('>')[0]

I tried to add .catch(err => console.log(err)) but nothing seems to change.

Thanks in advance! :)

The code you posted is not async, neither returns a promise. — lilezek, Sep 19 '17 at 17:34
`UnhandledPromiseRejectionWarning: Unhandled promise rejection (rejection id: 1): TypeError: Cannot read property 'catch' of undefined ` — Izio, Sep 19 '17 at 18:40

score 3 · Answer 1 · answered Sep 19 '17 at 17:36

Instead of catching, you can avoid an error by substituting a string when the first split produces no second index.

args[1] = (args[1].split('!')[1] || "").split('>')[0];

This assumes that args[1] is definitely present. If that's not certain, you can do a similar substitution.

args[1] = ((args[1] || "").split('!')[1] || "").split('>')[0];

And finally, you can provide a default value in case any part of that failed to produce something useful.

args[1] = ((args[1] || "").split('!')[1] || "").split('>')[0] || "DEFAULT";

score 0 · Answer 2 · answered Sep 19 '17 at 17:34

0

.catch(err => console.log(err)) is used to catch errors from promises. Use the standard form instead:

try{
    args[1] = args[1].split('!')[1].split('>')[0]
}
catch(err){
    console.log(err)
}

answered Sep 19 '17 at 17:34

Valera

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score 0 · Answer 3 · answered Sep 19 '17 at 17:35

More or less this is not promising. it's just a simple javascript statement which can be captured directly as below: Try using try catch on the whole

try{
   args[1] = args[1].split('!')[1].split('>')[0]
}catch(e){
console.log(e); 
// Most possible error would be TypeError: Cannot read property 'split' of undefined
at <anonymous>:1:23
}

Node - How to catch split() error?

3 Answers3