Check all active users from array

Question

I need to choose all active users with the easiest way

users = [{'id': 1, 'active': False}, {'id': 2, 'active': True}, {'id': 3, 'active': True}, {'id': 4, 'active': True}, {'id': 5, 'active': True}, {'id': 6, 'active': True}]

What exactly are you attempting to do? You want to return a list which only contains the dictionaries where `active` equals `True`? — Ethan Field, Sep 18 '17 at 13:12
Why not use ORM and filter active users in your query? How you get the `users` list? — Aamir Rind, Sep 18 '17 at 13:15

score 2 · Answer 1 · answered Sep 18 '17 at 13:09

2

You could do that with list comprehension,

active_users = [user for user in users if user['active']]

answered Sep 18 '17 at 13:09

zaidfazil

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score 2 · Accepted Answer · answered Sep 18 '17 at 13:09

2

Using a list comprehension would work fine:

users = [user for user in users if user['active']]

answered Sep 18 '17 at 13:09

aumo

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itzMEonTV · Answer 3 · 2017-09-18T13:17:38.467

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Use filter. It will return a list in py2.x and a generator for py3.x

filter(lambda x:x['active'], users)

edited Sep 18 '17 at 13:17

answered Sep 18 '17 at 13:14

itzMEonTV

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For anybody looking for a discussion of "should I use a list comprehension or filter": https://stackoverflow.com/questions/3013449/list-filtering-list-comprehension-vs-lambda-filter – Sep 18 '17 at 13:16
`x['active']` not `x['xctive']` – Aamir Rind Sep 18 '17 at 13:17

score 0 · Answer 4 · edited Sep 18 '17 at 13:46

0

active_user = [user['id']  for user in users if user['active']]

edited Sep 18 '17 at 13:46

bfontaine

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answered Sep 18 '17 at 13:18

im_w0lf

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Check all active users from array

4 Answers4