Jenkins launch job through DSL and do not wait for job to finish

Question

Im trying to launch a project through Jenkins DSL but dont need to wait for it to complete. Basically i want it to kick off an orphan job.

node("slave-node")
{
    // Launch pipeline job
    stage("LaunchPipelineJob")
    {
        // this step runs for x mins and does a buch of work
        echo "Starting pipelinejob"
        def pipelinejob  = build job: 'pipelineStep'
        //echo "Pipeline job status: ${pipelinejob.result}"
    }

    // Launch the orphan
    stage("LaunchOrphanJob")
    {
        // need to kick off this job, but dont care to wait for it to finish
        echo "Starting orphanPipelinejob"
        def orphanPipelinejob  = build job: 'orphanStep'
    }
}

i have looked over the dsl but cant find any docs on how to start an orphan. Thank you

score 9 · Answer 1 · answered Nov 29 '17 at 18:30

9

This should do it.

build job: 'pipelineStep', propagate: false, wait: false

answered Nov 29 '17 at 18:30

Onur Gokkocabas

194
1
11

score 6 · Answer 2 · edited Apr 21 '20 at 14:33

stage{
    build job: 'pipelineStep', parameters: [string(name: 'xxx', value: xxx), string(name: 'yyy', value: yyy)],wait:false
} 
stage{
    build job: 'orphanStep', parameters: [string(name: 'xxx', value: xxx), string(name: 'yyy', value: yyy)],wait:false
}

FYI, when you give, wait = false, The runwrapper won't return any object, so you will not be able to fetch any details related to child jobs (pipelineStep and orphanStep).

RunWrapper.html

Jenkins launch job through DSL and do not wait for job to finish

2 Answers2