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Block - 130.0.0.0/25 .
Want to create 8 subnet.

Binary Form of Block will be
1000 0010.0000 0000.0000 0000.0000 0000/25

Subnet mask would be
1111 1111.1111 1111.1111 1111.1000 0000

How will I make 8 subnetwork out of this?

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    See the excellent answer to [this question](https://networkengineering.stackexchange.com/q/7106/8499) for a complete description. – Ron Maupin Aug 23 '17 at 11:08

1 Answers1

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You can handle 2 ^ 7 = 128 IP's (binary form: 000 0000 - 111 1111). Each subnetwork will have 128 / 8 = 16 IP's. So the subnetworks will look as follows.

  1. 130.0.0.0 - 130.0.0.15
  2. 130.0.0.16 - 130.0.0.31
  3. 130.0.0.32 - 130.0.0.47
  4. 130.0.0.48 - 130.0.0.63
  5. 130.0.0.64 - 130.0.0.79
  6. 130.0.0.80 - 130.0.0.95
  7. 130.0.0.96 - 130.0.0.111
  8. 130.0.0.112 - 130.0.0.127
vadim_hr
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