One liner if - use condition in string

Question

Is there a way to use conditions in string?

$x = 'hello';
$y = 'mister'; // is nullable
$z = 'panda';

$msg = $x . ' ' . {($y == 'mister') ? 'dear ' : ' ' } . $z

// Output: hello dear panda

You have done it right, all you have to do is swap the curly brackets with parenthesis. — MinistryOfChaps, Aug 17 '17 at 06:51
@GergelyLukacsy, `{}` should be replaced with `()`, if removed it will return panda as output — Jigar Shah, Aug 17 '17 at 07:05

score 4 · Answer 1 · edited Aug 17 '17 at 07:10

4

You should replace the {} with (). Also, the () around the $y=='mister' are not needed. You should try to keep those to a (readable) minimum.

$msg = $x . ' ' . ($y == 'mister' ? 'dear ' : ' ' ) . $z;

edited Aug 17 '17 at 07:10

Martijn

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answered Aug 17 '17 at 06:53

Aakash Martand

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score 4 · Answer 2 · answered Aug 17 '17 at 06:59

4

for Ternary operator we are not using { } brackets,instead you have to use ( ).

Replace your code

$msg = $x . ' ' . {($y == 'mister') ? 'dear ' : ' ' } . $z

with

$msg = $x . ' ' . (($y == 'mister') ? 'dear ' : ' ' ) . $z

answered Aug 17 '17 at 06:59

Moby M

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score 3 · Answer 3 · answered Aug 17 '17 at 06:53

3

Replace {} with () and it will work:

$x = 'hello';
$y = 'mister'; // is nullable
$z = 'panda';
$msg = $x . ' ' . (($y == 'mister') ? 'dear ' : ' ' ) . $z;
echo $msg;

answered Aug 17 '17 at 06:53

u_mulder

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strange, Your answer is correct so why you down voted – Jigar Shah Aug 17 '17 at 07:01
@JigarShah we will never know) – u_mulder Aug 17 '17 at 07:03

score 0 · Answer 4 · answered Aug 17 '17 at 07:04

If I am understanding your question well, you do not intend to find out whether you can use a condition inside a string, but you want to assign a value to a string. The value to be assigned depends on a condition, which could be written like

$x = 'hello';
$y = 'mister'; // is nullable
$z = 'panda';

$msg = $x . ' ';
if ($y == 'mister') {
    $msg .= $x . 'dear ';
}
$msg .= $z;

// Output: hello dear panda

However, this is a bit long and you intended to use the ? operator. The mistake was that you used the curly brackets {}. This is the fix:

$x = 'hello';
$y = 'mister'; // is nullable
$z = 'panda';

$msg = $x . ' ' . (($y == 'mister') ? 'dear ' : ' ' ) . $z;

// Output: hello dear panda

One liner if - use condition in string

4 Answers4