#include <stdio.h>
#include <cstddef>
#include <cstring>
namespace /*namespace name generated by compiler*/
{
struct BB{};
}
struct AA{};
namespace my
{
inline void * memcpy(void*, const void*, std::size_t)
{
puts("CUSTOM IMPLEMENTATION");
return 0;
}
}
namespace my
{
void func()
{
AA a;
memcpy(&a, &a, sizeof(a)); // ambigious call for g++4.7 - g++6.2
BB b;
memcpy(&b, &b, sizeof(b)); // unambigious call
}
}
int main(int, char **)
{
my::func();
return 0;
}
Why memcpy is ambigious call here?
Please take a look at example with variable "i" in ANSI ISO IEC 14882, C++2003, 3.4.1, (6) (page 30). It "proves" that there is no ambigioty in such construction.
namespace A {
namespace N {
void f();
}
}
void A::N::f() {
i = 5;
// The following scopes are searched for a declaration of i:
// 1) outermost block scope of A::N::f, before the use of i
// 2) scope of namespace N
// 3) scope of namespace A
// 4) global scope, before the definition of A::N::f
}
Is unqualified lookup rules was broken in GCC or I did not understand something?