convert multi line string to single line

Question

Consider the following snippet

val myString =
  """
    |a=b
    |c=d
    |""".stripMargin

I want to convert it to a single line with delimiter ;

a=b;c=d;

I tried

myString.replaceAll("\r",";")

and

myString.replaceAll("\n",";")

but it didn't work.

You may need both "\r\n" if you are on Windows - it still thinks it's working with a teletype, and if it it doesn't end a line with carriage return, you terminal will start typing over the previous line ... — Dima, Aug 15 '17 at 13:27
Yes right but what if I use it is on Unix box after it is deployed.on local it is windows but deployment on unix — coder25, Aug 15 '17 at 14:15

score 5 · Accepted Answer · answered Aug 15 '17 at 09:11

5

I tried with \n and it works

scala> val myString = """
     | a=b
     | c=d
     | """.stripMargin
myString: String =
"
a=b
c=d
"

scala> myString.replaceAll("\n",";")
res0: String = ;a=b;c=d;

scala> res0.substring(1, myString.length)
res1: String = a=b;c=d;

I hope it helps

answered Aug 15 '17 at 09:11

Ramesh Maharjan

41,071
6
69
97

1

Using `System.lineSeparator()` instead of `"\n"` allows this to work on Windows – Kian Oct 11 '21 at 16:10

score 3 · Answer 2 · answered Jul 31 '20 at 14:45

Based on https://stackoverflow.com/a/25652402/5205022

"""
  |a=b
  |c=d
  |""".stripMargin.linesIterator.mkString(";").trim

which outputs

;a=b;c=d

or using single whitespace " " as separator

"""
  |Live long
  |and
  |prosper!
  |""".stripMargin.linesIterator.mkString(" ").trim

which outputs

Live long and prosper!

score 1 · Answer 3 · answered Sep 22 '20 at 22:28

Because it is the first Google result at "Scala multiline to a single line" and the question is pretty general. It may be reasonable to add an implicit way:

implicit class StringExtensionImplicits(s: String) {

    def singleLine: String = {
      singleLine('|')
    }

    def singleLine(marginChar: Char): String = {
      s.stripMargin(marginChar).replace('\n', ' ')
    }

}

Now you can:

logger.info(
  """I'm a so long log entry that some devs who like vim don't like me.
    |But you can help them to keep patience.""".singleLine)

score 0 · Answer 4 · answered Aug 15 '17 at 09:07

0

Try this

myString.split("\n").filter(_.nonEmpty).mkString("",";",";")

answered Aug 15 '17 at 09:07

Dhirendra

289
3
8

score 0 · Answer 5 · answered Jun 08 '22 at 08:15

0

If someone want to find how to create multiline strings:

val myString = "This is " +
               "my string"

which output is This is my string. You can also use s strings here to implement variables

answered Jun 08 '22 at 08:15

Yauheni Leaniuk

418
1
6
15

score 0 · Answer 6 · answered Apr 06 '23 at 08:54

0

You can use

    val myString =
      """
        |a=b
        |c=d
        |""".stripMargin.lines.mkString(";")

linesIterator is deprecated since scala 2.11

answered Apr 06 '23 at 08:54

Ayoub Omari

806
1
7
24

convert multi line string to single line

6 Answers6