c# regex find 2 isolated char in password

Question

i didn't find another solution for this specific problem, so i hope you guys can help.

I need to test if a given password has 2 or more uppercase letters and i want to use regular expressions to do so. what i have now is this:

if (Regex.IsMatch(passw, @"([A-Z]){2,}")){
            Note += 1;
        }

only regular expression:

@"([A-Z]){2,}"

but with this code the programm only works if there are 2 ore more uppercase letters next to each other.

this works: aAAa

this doesn't: aAaA

but i need the latter as password can be fully random.

i searched around the web about regular expressions, but {2,} seem to be the best quantifier for the job, or am i completly wrong there?

thanks for any tipps :)

You need to know count upper case in password or what? – Feras Al Sous Aug 14 '17 at 06:14 — Feras Al Sous, Aug 14 '17 at 06:14

score 0 · Answer 1 · answered Aug 14 '17 at 06:12

0

This should do the job

@"[A-Z].*[A-Z]"

Here you search for an uppercase letter ([A-Z]), then any string (.*), and then another uppercase letter ([A-Z]). If you want to be able to increase the number of required uppercase letters easily you can use this:

@"([A-Z].*){2,}"

Now you look for an uppercase letter, then any string. And you search for this twice or more.

answered Aug 14 '17 at 06:12

EarthDragon

755
4
14

Thank you very much :) that was exactly the solution i needed. – Nazzaroth Aug 14 '17 at 10:17
So accept it, please! – EarthDragon Aug 15 '17 at 10:35

score 0 · Answer 2 · answered Aug 14 '17 at 06:19

0

You can use this code to find count upper case and digit in password:

return password.Length >= z
    && new Regex("[A-Z]").Matches(password).Count >= x
    && new Regex("[0-9]").Matches(password).Count >= y
    ;

i hope to help you.

answered Aug 14 '17 at 06:19

Feras Al Sous

1,073
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c# regex find 2 isolated char in password

2 Answers2