Use 'df -h' to check % remaining disk space of a specific folder

Question

I am using 'df -h' command to get disk space details in my directory and it gives me response as below :

Now I want to be able to do this check automatically through some batch or script - so I am wondering, if I will be able to check disk space only for specific folders which I care about, as shown in image - I am only supposed to check for /nas/home that it does not go above 75%.

How can I achieve this ? Any help ?

My work till now:

I am using

df -h > DiskData.txt

... this outputs to a text file

grep "/nas/home" "DiskData.txt"

... which gives me the output:

*500G  254G  247G  51% /nas/home*

Now I want to be able to search for the number previous or right nearby '%' sign (51 in this case) to achieve what I want.

Yes, you can do check. But what do you want to do if it's more than 75% ? You can write bash script and put it to crontab, so you can automate periodical check — Alex Kapustin, Aug 14 '17 at 04:01
I want to actually send a mail that it is more than 75% but as of now an echo would do, check the updated question — dynamicJos, Aug 14 '17 at 04:14

nagendra547 · Accepted Answer · 2017-08-14T04:48:29.757

5

This command will give you percentage of /nas/home directory

df /nas/home | awk '{ print $4 }' | tail -n 1| cut -d'%' -f1

So basically you can use store as value in some variable and then apply if else condition.

var=`df /nas/home | awk '{ print $4 }' | tail -n 1| cut -d'%' -f1`
if(var>75){
#send email
}

edited Aug 14 '17 at 04:48

answered Aug 14 '17 at 04:32

nagendra547

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**df /nas/home | awk '{ print $5 }' | tail -n 1| cut -d'%' -f1** gives - _/nas/home_ not **51** – dynamicJos Aug 14 '17 at 04:40
can you provide output of following command 'df /nas/home' – nagendra547 Aug 14 '17 at 04:41
Filesystem 1K-blocks Used Available Use% Mounted on d2cnas:/dev_home 524288000 266297856 257990144 51% /nas/home – dynamicJos Aug 14 '17 at 04:45
the above is the output for df /nas/home – dynamicJos Aug 14 '17 at 04:45
I have updated my solution. try once now. use df /nas/home | awk '{ print $4 }' | tail -n 1| cut -d'%' -f1 – nagendra547 Aug 14 '17 at 04:48
I have one more question, can something like this _df /nas/home | awk '{ print $4 }' | tail -n 1| cut -d'%' -f1_ be done in windows command prompt ? – dynamicJos Aug 14 '17 at 06:22
you can use `df /nas/home|awk '/Filesystem/{getline;print $4}'` or `df /nas/home|awk '/Filesystem/{getline;print $3}'` no need to use multiple pipes – P.... Aug 14 '17 at 06:32

beliy · Answer 2 · 2017-08-14T08:58:20.647

3

another variant:

df --output=pcent /nas/home | tail -n 1 | tr -d '[:space:]|%'

output=pcent - show only percent value (for coreutils => 8.21 )

edited Aug 14 '17 at 08:58

answered Aug 14 '17 at 05:17

beliy

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share your output pls – beliy Aug 14 '17 at 08:19
version coreutils? – beliy Aug 14 '17 at 08:58
df: unrecognized option '--output=pcent' Try `df --help' for more information. – dynamicJos Aug 14 '17 at 10:32
1

u have version coreutils less than 8.21 (u can check with `df --version`) – beliy Aug 14 '17 at 10:35

score 1 · Answer 3 · answered Aug 14 '17 at 07:06

1

A more concise way without extensive piping could be:

df -h /nas/home | perl -ane 'print substr $F[3],0,-1 if $.==2'

Returns: 51 for your example.

answered Aug 14 '17 at 07:06

reflective_mind

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Use 'df -h' to check % remaining disk space of a specific folder

3 Answers3