How to access object in php when the identifier starts with a @ symbol?

Question

I have a json object that looks like this:

{#119130 ▼
  +"@id": "1EBEF5DA"
  +"@name": "The"
  +"@renewal": "xxxxx"
  +"@languages": "Eng"
}

How do I access a the JSON data in php when the identifier starts with an @ symbol?

For example trying to access it using $var->@id results in an error:

Parse error: syntax error, unexpected '@', expecting identifier (T_STRING) or variable (T_VARIABLE) or '{' or '$'

I tried $var->id but it results in an Undefined Property.

You can try accessing it via `$var['@id']`. If this works I will add it as an answer for you. — cramopy, Aug 12 '17 at 08:54
why would the json property be prefixed with an `@`? It's not invalid, but what's the point? — Gordon, Aug 12 '17 at 09:11
@Gordon not sure why the clients developers did it this way. This is just the response I get from the clients server and was supposed to process it. — kevinabraham, Aug 12 '17 at 09:40

score 6 · Answer 1 · answered Aug 12 '17 at 09:00

6

Use this:

$a = '{"@id":"123","@idx":"2232"}';
$b = json_decode($a);
print_r($b);
echo $b->{'@id'};

answered Aug 12 '17 at 09:00

d_void

Niklesh Raut · Accepted Answer · 2017-08-12T09:22:55.487

4

Keep element name in one variable like $test and use $var->$test to get value like this

 <?php
    $arr = json_decode(json_encode(["@id"=> "1EBEF5DA"]));
    $obj = '@id';
    print_r($arr->$obj);
 ?>

Or another way is print_r($arr->{'@id'});

edited Aug 12 '17 at 09:22

answered Aug 12 '17 at 08:57

Niklesh Raut

1

Thanks @user2486. `$arr->{'@id'}` solved my problem. – kevinabraham Aug 12 '17 at 09:39
Thanks, $arr->{'@id'} worked for my usecase when accessing Microsoft Azure. – Matthew Jones Aug 08 '22 at 15:33

score 3 · Answer 3 · edited Aug 12 '17 at 09:02

3

Try it like this:

$idFieldName = '@id';
$var->$idFieldName;

edited Aug 12 '17 at 09:02

Nigel Ren

answered Aug 12 '17 at 08:59

Drusantia

3 Answers3