django display content of a manytomanyfield

Question

I started using django framework just a few days ago and i desperately need some help with my application.

It consists of client,project,admin,and admin payment classes where the admin_payment holds the ids of the admins and projects among other stuff.

My question is how i can display the "administrator's name" of each "project" in my admin listing of projects? the project class itself does not hold the administrator ids (the Admin_Payment does)

Currently i have the following structure: (striped down)

models.py

class Admin(models.Model):
    admin_name = models.CharField(unique = True, blank = False, null = False, max_length = 128, verbose_name = u'admin full name')

    def __unicode__(self):
        return self.admin_name
    class Meta:
        ordering = ('id',)
        verbose_name = u'Admin Info'

class Project(models.Model):
    client = models.ForeignKey(Client, verbose_name = u'Client')
    description = models.ForeignKey(Description, verbose_name = u'project description')
    admins = models.ManyToManyField(Admin, verbose_name = u'Administrators', through = 'Admin_Payment')

class Admin_Payment(models.Model):
    admin = models.ForeignKey(Admin, verbose_name = u'Administrator')
    project = models.ForeignKey(Project, verbose_name = u'project')

admin.py (striped down)

class AdminInline(admin.TabularInline):
    model = Admin

class ProjectAdmin(admin.ModelAdmin):
    radio_fields = {'position': admin.HORIZONTAL, 'solution': admin.HORIZONTAL}
    inlines = [AdminInline, ]
    list_display = ['client','description','admin_name']

Clients and Descriptions appear correctly in the project listing but the admin names are not

Any help is appreciated (sorry if i posted anything that doesnt make sense , i am a newbie in python and django)

Bernhard Vallant · Accepted Answer · 2010-12-31T19:33:43.607

29

Displaying the contents of ManyToMany field isn't supported by default by django, because the database will be queried for each row of the results. You can display it yourself by adding a method to your Project-model:

class Project(models.Model):
    ....
    def admin_names(self):
        return ', '.join([a.admin_name for a in self.admins.all()])
    admin_names.short_description = "Admin Names"

and put admin_names in your list_display fields!

edited Dec 31 '10 at 19:33

answered Dec 30 '10 at 16:44

Bernhard Vallant

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That worked great thanks. Any idea how i can add a filter for each admin? – Thordin9 Dec 30 '10 at 22:49
is it possible to add a verbose_name to the returned value? – Thordin9 Dec 31 '10 at 18:40
@Thordin9: i've added the answer to fit yourquestion, additionally see the doc at http://docs.djangoproject.com/en/dev/ref/contrib/admin/#django.contrib.admin.ModelAdmin.list_display – Bernhard Vallant Dec 31 '10 at 19:34
Useful answer. If you want to add the value from the `__unicode__` method on your model without rewriting it, try: `return ', '.join([str(a) for a in self.admins.all()])`. It works fine if you don't use the `__str__` method [as stated on documentation](https://docs.djangoproject.com/en/dev/ref/models/instances/?from=olddocs#unicode). – chirale Oct 17 '12 at 15:13
Is there a way to show this collection in nested list? – Moe Far Jan 21 '16 at 14:49

django display content of a manytomanyfield

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