Is there a way to find all branches created from a SVN branch?

Question

I'm trying to list all branches created from a Parent SVN branch to establish a graphical representation of a branch in Subversion.
Are there any SVN command which can be used to achieve this?
Or is there an approach to solve this?

Example:

Parent Branch: Branch1
Child Branch: Branch2 and Branch3 (both branches created from Branch1).
GrandChildren Branch: Branch2.1, Branch3.1 etc.,
Given Branch1, I'm trying to list the child branches and Grand Children branches that were created from Parent Branch (Branch1) and Child Branches respectively.

Result:

Branch1-------------------Branch2-------Branch2.1 , Branch 2.2 ..
|__________________Branch3-------Branch3.1, Branch3.2...

score 1 · Answer 1 · answered Nov 29 '17 at 16:14

I had a similar problem to solve. However I have limited my search to the children. Making a recursive script will let you find the grand children.

Because the repository I have to examine has a lot of branches and commits, svn log commands can be very slow. So, I separated the work in two steps:

Retrieve the commits logs that create the Children branches. I save them in a file, with a one line:
```
parent='/branches/2014/new-components'
svn log  https://svn.abc.org/branches/ -r1903:HEAD -v | ack -C2 "A.+\(from ${parent}:[0-9]+" >> kids.log
```
The -r1903 is to limit the search to try speed up things a bit. I knew the parent branch was created at r1903, so no need to look before.

I used ack, but grep would work the same.

I wrote a python 2.7 script to parse the kids.log file:

from __future__ import print_function

import re
import subprocess

parser = argparse.ArgumentParser()
parser.add_argument("file", help="svn log file to parse")
args = parser.parse_args()

parent='/branches/2014/new-components'

# Regexp to match the svn log command output
#    1st match = revision number
#    2nd match = author
#    3rd match = date of creation
#    4th match = branch path
#    5th match = 1st line of commit message

my_regexp = re.compile(r'r([0-9]+) \| (.+) \| ....-..-.. ..:..:.. \+.... \((.+)\) \| [0-9]+ lines?\n'
                       'Changed paths:\n'
                       ' *A (.+) \(from '+parent+':[0-9]+\)\n'
                       '\n'
                       '(.+)\n')

with open(args.file, 'r') as f:
    matches = my_regexp.finditer(f.read())

# print kids name
bnames =  [m.group(4) for m in matches]
print('\n'.join(bnames))

Tip: I replace the last two lines with the following to gather all the matches:

allinfo = [[m.group(i) for i in range(1,6)] for m in matches]

then you can loop over allinfo and print out the information you need as you want.

Grand kids: To make a recursive script, steps 1 and 2 have to be converted into functions in one python script. And step 2 would call step 1 with the found kids name as argument. Objects may help keeping track of the entire family tree.

Is there a way to find all branches created from a SVN branch?

1 Answers1