Python win32 service starting automatically

Question

I am writing a python win32 service below are snippet of my code when i compile the service it works but i need to go to services.msc and start it manually.

Is there an option when i install the serivce by : myservice.exe install it will starts automaticly ?

below are snippet of my code :

import win32serviceutil
import win32service
import win32event

class SmallestPythonService(win32serviceutil.ServiceFramework):
   _svc_name_ = "ser_name"
   _svc_display_name_ = "ser_descryption"
   #_svc_description_='ddd'
   def __init__(self, args):

      win32serviceutil.ServiceFramework.__init__(self, args)
                    self.hWaitStop = win32event.CreateEvent(None, 0, 0, None)

    def SvcStop(self):

       self.ReportServiceStatus(win32service.SERVICE_STOP_PENDING)
       win32event.SetEvent(self.hWaitStop)

   def SvcDoRun(self):

       win32event.WaitForSingleObject(self.hWaitStop, win32event.INFINITE)

if __name__=='__main__':

    win32serviceutil.HandleCommandLine(SmallestPythonService)

score 18 · Answer 1 · answered Oct 01 '14 at 21:27

18

Use myservice.exe --startup=auto install to install the service and set it to be started automatically.

answered Oct 01 '14 at 21:27

Maciejg

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Nativ solution is best solution! – enthus1ast Oct 28 '14 at 13:04

score 2 · Answer 2 · answered Dec 27 '10 at 16:34

2

I would take a look at this ActiveState recipe. It's a wrapper around the win32serviceutil that shows how to auto-start the service.

answered Dec 27 '10 at 16:34

Mark

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score 1 · Answer 3 · answered Dec 27 '10 at 13:22

1

You can use sc.exe with the create command.

sc create MyPyService binPath= "C:\myservice.exe" DisplayName= "Some Python Service"

More on this at Microsoft KB251192.

win32serviceutil also has a InstallService() function you might be able to use.

answered Dec 27 '10 at 13:22

kichik

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when i start the service using `sc start MyPyService` i get the error. `[SC] StartService FAILED 1053: The service did not respond to the start or control request in a timely fashion.` – programmer Oct 08 '21 at 05:28

score -1 · Answer 4 · answered Mar 03 '16 at 11:00

-1

@Maciejg doesn't work for me, here the solution to start automaticaly my service builded with py2exe :

myservice.exe -auto -install

answered Mar 03 '16 at 11:00

Guillaume Vincent

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Python win32 service starting automatically

4 Answers4