Best way to repeat an observable every minute rxjava

Question

I have the following method:

public class ParentalControlInteractor {
   public Single<Boolean> isPinSet() {
       return bamSdk.getPinManager().isPINSet();
   }
}

I want to call this function to run once, then repeat every minute until infinity but this seems clumsy:

    parentalControlInteractor.isPinSet()
            .subscribeOn(Schedulers.io())
            .repeat(10000)
            .timeout(1600,TimeUnit.MILLISECONDS)
            .doOnError(throwable -> {
                Timber.e(throwable,"Error getting if Pin is set");
                throwable.printStackTrace();
            })
            .subscribe(isPinSet -> {
                this.isPinSet = isPinSet;
                Timber.d("Pin is set = " + isPinSet.toString());
                });

Isn't there a better way to do it? I'm using RxJava2. Also, the method above only calls it 10000 times. I want to call it forever, like using Handler.postDelayed().

just call `repeat()` pass no parameter to it to repeat forever — bbsimon, Jul 28 '17 at 14:53
I don't want it to keep calling this every second, I'd like there to be an interval. — Kristy Welsh, Jul 28 '17 at 14:58

Mohamed Ibrahim · Answer 1 · 2019-10-04T10:28:06.987

16

you can use interval() oberator here is the code

DisposableObserver<Boolean> disposable = 
Observable.interval(1, TimeUnit.MINUTES)
            .flatMap(aLong -> isPinSet().toObservable())
            .subscribeOn(Schedulers.io())
            .subscribeWith({isPinSet -> doSomething()}, {throwable -> handleError()}, {});

if you want to finish this operation at any time call disposable.dispose()

edited Oct 04 '19 at 10:28

answered Jul 29 '17 at 12:15

Mohamed Ibrahim

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score 8 · Answer 2 · edited Mar 20 '19 at 15:04

8

Try .repeatWhen(objectFlowable -> Flowable.timer(10, TimeUnit.SECONDS).repeat())

edited Mar 20 '19 at 15:04

Igor Dvorzhak

4,360
3
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answered Mar 20 '19 at 14:04

vadimqa08

81
1
1

score 6 · Answer 3 · answered Jul 28 '17 at 15:02

Try this:

parentalControlInteractor.isPinSet()
        .subscribeOn(Schedulers.io())
        .repeatWhen(new Func1<Observable<? extends Void>, Observable<?>>() {
            @Override
            public Observable<?> call(Observable<? extends Void> observable) {
                return observable.delay(60, TimeUnit.SECONDS);
            }
        })
        .doOnError(throwable -> {
            Timber.e(throwable,"Error getting if Pin is set");
            throwable.printStackTrace();
        })
        .subscribe(isPinSet -> {
            this.isPinSet = isPinSet;
            Timber.d("Pin is set = " + isPinSet.toString());
        });

I'm not sure what exception @KristyWelsh is referring to, but this approach seems to work fine. — mdelolmo, Mar 01 '18 at 10:05

score 6 · Accepted Answer · answered Jul 28 '17 at 19:49

6

It turns out this is doing the job:

parentalControlInteractor.isPinSet()
            .subscribeOn(Schedulers.io())
            .delay(10000,TimeUnit.MILLISECONDS)
            .repeat()
            .doOnError(throwable -> {
                Timber.e(throwable,"Error getting if Pin is set");
                throwable.printStackTrace();
            })
            .subscribe(isPinSet -> {
                this.isPinSet = isPinSet;
                Timber.d("Pin is set = " + isPinSet.toString());
                });

answered Jul 28 '17 at 19:49

Kristy Welsh

7,828
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106

2

does this run the first time right away or will delay also the first time? – AmirG Mar 30 '18 at 13:42
I believe it delays the first time. – Kristy Welsh Mar 30 '18 at 19:53
1

How to stop the process ? – Kalanidhi Aug 08 '19 at 12:13
this will just delay the result 10 seconds, it will not repeat, please check my answer – Mohamed Ibrahim Oct 20 '19 at 14:40

score 5 · Answer 5 · answered Sep 12 '18 at 10:06

5

Best way to repeat request every time with specific delay of first emission

 return Observable.interval(FIRST_ITEM_DELAY, CYCLE_TIME, TimeUnit.SECONDS)
                       .flatMap(aLong -> repository.repeatedRequest());

answered Sep 12 '18 at 10:06

Andrew Evtukhov

423
1
6
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score 0 · Answer 6 · answered Jun 01 '18 at 15:11

0

You can combine some RxJava operators:

Observable.wrap(parentalControlInteractor.isPinSet().delay(1,TimeUnit.MINUTES)).repeat();

I found this solution very elegant and very simple

answered Jun 01 '18 at 15:11

Giuseppe Giacoppo

425
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Best way to repeat an observable every minute rxjava

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