__stdcall typedef g++ problem

Question

This code compiles (as I would expect):

typedef void __stdcall (*Func)();

struct A {
    static void __stdcall f() { }
};

int main() {
    Func p = A::f;
}

But this one:

struct A {
    typedef void __stdcall (*Func)();
    static void __stdcall f() { }
};

int main() {
    A::Func p = A::f;
}

fails with not-very-helpful error message:

error: invalid conversion from `void (*)()' to `void (*)()'

I'm using g++ 3.4.2 under Vista (I know, it's ancient, but I don't have access to any other environment right now). Obviously I am missing something here. Any help would be appreciated.

What are you trying to achieve. In C ot is common to get the address of a function. in C++ it is very rare to need the address of a function or method. — Martin York, Dec 26 '10 at 20:11

score 7 · Accepted Answer · answered Dec 26 '10 at 18:21

7

The syntax is void(__stdcall *)(), not void __stdcall (*)().

answered Dec 26 '10 at 18:21

Puppy

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That was a simple answer. Thank you! – jhh Dec 26 '10 at 18:42

__stdcall typedef g++ problem

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