Passing Variables to Start-Job

Question

I have to be missing something incredibly simple here. Here's a very basic script to illustrate what I'm trying:

$Computers = @('comp1', 'comp2')

$ScriptBlock = {
    New-Item "C:\Temp\$C.txt" -Force
}

Foreach ($C in $Computers)
{
    Start-Job -ScriptBlock $ScriptBlock -ArgumentList $C
}

The script runs, but $C is not passed, so i just get a ".txt" file in my folder. What simple thing am I overlooking here?

`New-Item "C:\Temp\$($args[0]).txt" -Force` – user4003407 Jul 25 '17 at 17:06 — user4003407, Jul 25 '17 at 17:06
Alternately, your scriptblock needs a `param($C)` line. – TessellatingHeckler Jul 25 '17 at 17:08 — TessellatingHeckler, Jul 25 '17 at 17:08

score 3 · Accepted Answer · answered Jul 25 '17 at 17:35

3

Replace this:

$ScriptBlock = {
    New-Item "C:\Temp\$C.txt" -Force
}

With this:

$ScriptBlock = 
{
    param($C)
    New-Item "C:\Temp\$C.txt" -Force
}

Note: When you are passing the arguments in the argumentlist , then make sure the same number of arguments have to accepted inside the scriptblock by using param.

answered Jul 25 '17 at 17:35

Ranadip Dutta

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Something simple indeed. Hopefully I can take this bit of knowledge and apply it to the more complicated script I'm working on. – Tchotchke Jul 25 '17 at 18:09
@Tchotchke: Happy to guide you. enjoy scripting with PS – Ranadip Dutta Jul 26 '17 at 04:38

Passing Variables to Start-Job

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