flask script file structure

Question

what does "python manage.py runserver" runs in situation below. It does not run main.py or app package.

flask

myApp          
    main.py

bash> python main.py

flask_script

manage.py
myApp
    __init__.py
    main.py

bash> python manage.py runserver

manage.py

from flask_script import Manager
from myApp import app

manager = Manager(app)

if __name__ == "__main__":
    manager.run()

main.py

from flask import Flask
app = Flask(__name__)  

@app.route('/')
def hello():   
    return "Hello World"

if __name__ == '__main__':
    app.run(debug=True)

and __init__.py is empty

Please feel free to explain what is wrong with my way of questioning. — ali shirzad, Jul 23 '17 at 06:58
Giving minuses with no explanation makes communication in this community very difficult and frustrating. — ali shirzad, Jul 23 '17 at 21:13

ali shirzad · Answer 1 · 2017-07-23T09:01:01.523

I answer my own questions since i get arbitrary minuses whenever i ask anything in this warm and welcoming community.

I found "a way" maybe not "the way".

file structure

|manage.py
|myApp
  |__init__.py
  |main.py
  |blog
    |__init__.py
    |blog.py

manage.py

from flask_script import Manager
from flask import Flask

from myApp.main import interface as main_inaterface
from myApp.blog.blog import interface as blog_interface

app.register_bluprint(main_interface, url_prefix='/main')
app.register_bluprint(blog_interface, url_prefix='/blog')

manager = Manager(app)

if __name__ == '__main__':
    manager.run()

myApp.__ init __.py

from flask import Flask
app = Flask(__name__)

import myApp

main.py

from flask import Blueprint

interface = Blueprint('myApp', __name__)

@interface.route('/')
def hello():
    return "from main"

blog

from flask import Blueprint

interface = Blueprint('blog', __name__)

@interface.route('/')
def blog():
  return "From Blog"

flask script file structure

1 Answers1