SWIFT 3 Thread 1: EXC_BAD_INSTRUCTION(code=EXC_1386_INVOP,subcode=0*0)

Asked Jul 21 '17 at 17:04

Active Jul 21 '17 at 17:14

Viewed 81 times

let roupa1: [String: String] = ["ID": "H1", "Descricao": "Roupa bacana!", "Preco": "40$"]
var roupasArray = [Dictionary<String, String>()]
roupasArray.append(roupa1)

UserDefaults.standard.set(roupasArray, forKey: "Roupas")

if let objecto = UserDefaults.standard.object(forKey: "Roupas") as? Array<Dictionary<String, String>>{
    lbtest.text = (objecto[0]["ID"])
}

Can someone help me? I am new at swift 3.0 and looked everywhere but can't find a solution

edited Jul 21 '17 at 17:14

rmaddy

314,917
42
532
579

asked Jul 21 '17 at 17:04

Carlos Costa

What happens when the array has less then 2 elements, and you try to access the second (index 1) element? – Alexander Jul 21 '17 at 17:08
1

Do not post code as an image. Please [edit] your question and copy and paste actual code, as text, into your question. – rmaddy Jul 21 '17 at 17:09
With the code on the image above he makes the array where the first object is empty and the second has imformation – Carlos Costa Jul 21 '17 at 17:11
Which line is causing the error? – rmaddy Jul 21 '17 at 17:15
lbtest.text = (objecto[0]["ID"]) – Carlos Costa Jul 21 '17 at 17:15
Verify your `latest` outlet is connected. – rmaddy Jul 21 '17 at 17:16
Most likely you mean `var roupasArray = [Dictionary]()` – vadian Jul 21 '17 at 17:16
Thanks rmaddy. I don't know why but sometimes the Xcode deletes the connections! – Carlos Costa Jul 21 '17 at 17:20

SWIFT 3 Thread 1: EXC_BAD_INSTRUCTION(code=EXC_1386_INVOP,subcode=0*0)

0 Answers0