I'm trying to give condition in my Middleware
.
Here is my script
if (auth()->check() && auth()->user()->type == 'TP001') {
$menu->add("User Control",array('nickname' => "user",'class'=>'treeview'))
->append(' <b class="caret"></b>')
->prepend('<span class="glyphicon glyphicon-user"></span> ');
$menu->user->add('Daftar User','user/list');
$menu->user->add('Tipe User','user/type');
} else {
/* Some code here...*/
}
The script above I cants see the menu with the condition even I already login with 'TP001'
(always in else), then I try to fix my code with this
auth()->user()->isDeveloper()
My model
public function isDeveloper()
{
return ($this->type == 'TP001');
}
But still not working, is there any way to give the condition like above but in a correct way? Thanks in advance and sorry for my bad English.
My Kernel
protected $middleware = [
\Illuminate\Foundation\Http\Middleware\CheckForMaintenanceMode::class,
\Illuminate\Foundation\Http\Middleware\ValidatePostSize::class,
\App\Http\Middleware\TrimStrings::class,
\Illuminate\Foundation\Http\Middleware\ConvertEmptyStringsToNull::class,
\App\Http\Middleware\Frontend::class,
];