overriding in java:how method call is resolved?

Question

class Y{
    void process(){
        System.out.println("In Y process()");
    }
}

class I extends Y{
    void process(){
        System.out.println("In I process()");
    }

    public static void main(String[] args){
        Y y = new I();
        y.process();
    }
}

this code is based on overriding in java .but I have a doubt regarding this problem.when we call the process method using y reference variable then is the method call resolved at runtime or is it resolved by the compiler?please help me out with this problem that whether the JVM reolves which process method is to be called or is it the compiler?give reason for your answer.

Please take the time to format your code when posting. It's very hard to read without any indentation. Additionally, this topic has been covered multiple times - and at least *some* of it should be answerable just by the output of your test app. — Jon Skeet, Jul 14 '17 at 16:00
Possible duplicate of [How to call the overridden method of a superclass](https://stackoverflow.com/questions/15668032/how-to-call-the-overridden-method-of-a-superclass) — Blasanka, Jul 14 '17 at 16:01
Who mentioned anything about errors? If you ran your code, you should have the answer to your question. — shmosel, Jul 14 '17 at 18:30

score 0 · Answer 1 · edited Jul 14 '17 at 18:20

0

The method is resolved at runtime, you are extending a class and this mean that this class can have the same methods as the parent class but the reference is resolved at runtime.

edited Jul 14 '17 at 18:20

Andrew Li

55,805
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143

answered Jul 14 '17 at 16:05

Ivan Lynch

563
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score 0 · Answer 2 · answered Jul 14 '17 at 17:10

0

This is called runtime polymorphism.Here method of class I will be executed .Always reference type of object is checked at run time.Suppose process method is not present in parent class then that is overriding and it will generate error.

answered Jul 14 '17 at 17:10

Ankit

49
1
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score 0 · Answer 3 · answered Jul 14 '17 at 19:38

This call will resolve at runtime. And the process() method of I class will gets exucuted. The Superclass reference is refering to the child class object. So when you call the method using superclass reference who is refereing to the child class object, always child class method will gets executed.

overriding in java:how method call is resolved?

3 Answers3