Error in replacing pattern with `sed` command

Asked Jul 14 '17 at 14:11

Active Jul 14 '17 at 14:25

Viewed 63 times

I am trying to replace occurrences of pattern in a file. Lines in the file look like this:

****time is = 0000
****time is = 0001

I am trying to search string by case insensitive time is and want to replace time is = xxxx by ****.

I tried using sed 's/time \ is/.*' filename.txt

But I get error sed: -e expression #1, char : unterminated 's' command

Any suggestions?

Update

I corrected the command. sed 's/time \ is/.*/' filename.txt But this places .* = xxxx This is not I wanted. I wanted to replace the entire pattern by ****.

Original line: ****time is = 0000

Desired output: ********

Any sugegstions?

edited Jul 14 '17 at 14:25

asked Jul 14 '17 at 14:11

er34456

1

If you really typed it that way, you are missing the closing quote after the asterisk. – alzee Jul 14 '17 at 14:13
Sorry that was typo in question. Corrected. – er34456 Jul 14 '17 at 14:18
1

you are missing ending '/' as well. – sahaj Jul 14 '17 at 14:18
Please show the desired output for your sample input. Your current description can be read as if you want "********" for both input lines as resulting output. – Yunnosch Jul 14 '17 at 14:22
Updated question – er34456 Jul 14 '17 at 14:27
is this what you are looking for? `sed 's/time is.*/****/' filename.txt`.. regarding case insensitive, if see if your sed supports `i` or `I` flag.. `'s/time is.*/****/I'`... else, you can use `'s/[tT][iI][mM][eE] [iI][sS].*/****/'` – Sundeep Jul 14 '17 at 15:30
Yes. Thanks. Can you explain what `.*` in `time is.*` does? – er34456 Jul 14 '17 at 17:16
@er34456 `.*` is a regular expression that matches everything. – John Goofy Jul 15 '17 at 12:40

Error in replacing pattern with `sed` command

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