Qt signal on buttongroup not connected

Question

I have a buttongroup defined with two radiobuttons

buttonGroupFFTDimension = new QButtonGroup(this);
buttonGroupFFTDimension->addButton(ui->radioButton1D, 1);
buttonGroupFFTDimension->addButton(ui->radioButton2D, 2);
buttonGroupFFTDimension->setExclusive(true);
ui->radioButton1D->setChecked(true);

The connect also compiles

connect(this->buttonGroupFFTDimension, static_cast<void(QButtonGroup::*)(int)>(&QButtonGroup::buttonClicked),
        this, &MainWindow::on_buttonGroupFFTDimension_buttonClicked);

but it throws and error at runtime

QMetaObject::connectSlotsByName: No matching signal for on_buttonGroupFFTDimension_buttonClicked(int)

I admit that I am not familiar with the new connect syntax, but also do not see the obvious error. What is wrong?

You could show how you define the slot: `on_buttonGroupFFTDimension_buttonClicked` — eyllanesc, Jul 14 '17 at 14:16
The message shown is because you are using `Qt Designer` and it uses the `connectSlotsByName` method to connect various elements, it recognizes the format `on_somesender_somesignal`, and in your case matches your slot, try changing the name of your slot, run `make clean` and then `qmake`. — eyllanesc, Jul 14 '17 at 14:19

eyllanesc · Accepted Answer · 2017-07-14T14:39:35.517

The message shown is because you are using Qt Designer and it uses the connectSlotsByName method to connect various elements, it recognizes the format on_somesender_somesignal, and in your case matches your slot.

First solution: It iss unnecessary to use the connect function, this will automatically do it. Also I think that the slot does not have as parameter the type int that requires.

In your case the slot should be as follows:

private  slots:
    void on_buttonGroupFFTDimension_buttonClicked (int val);

Another possible solution is to rename the slot, after that you run make clean and qmake.

Qt signal on buttongroup not connected

1 Answers1