I have such a string:
msg='123abc456def'
Now I need to split msg and get the result as below:
['123', 'abc', '456', 'def']
In python, I can do like this:
pattern = re.compile(r'(\d+)')
res = pattern.split(msg)[1:]
How to get the same result in bash script?
I've tried like this but it doesn't work:
IFS='[0-9]' # how to define IFS with regex?
echo ${msg[@]}
Getting the substrings with grep, and putting the output in an array using command substitution:
$ msg='123abc456def'
$ out=( $(grep -Eo '[[:digit:]]+|[^[:digit:]]+' <<<"$msg") )
$ echo "${out[0]}"
123
$ echo "${out[1]}"
abc
$ echo "${out[@]}"
123 abc 456 def
[[:digit:]]+|[^[:digit:]]+ matches one or more digits ([[:digit:]]+) OR (|) one or more non-digits ([^[:digit:]]+.
Given that you already know how to solve this in Python, you can solve it using the code shown in the question:
MSG=123abc456def;
python -c "import re; print('\n'.join(re.split(r'(\\d+)', '${MSG}')[1:]))"
While python is not as standard of an executable as say grep or awk, does that really matter to you?
I would do matching instead of splitting. Here, I used grep but you can use the same regex in pure bash also.
$ msg='123abc456def'
$ grep -oE '[0-9]+|[^0-9]+' <<<$msg
123
abc
456
def
