ruleYear :: Rule
ruleYear = Rule
{ name = "year"
, pattern=[regex "[12]\d{3})|(([\.\/\-\'])[901]\d)"]
--pattern = [Predicate $ isIntegerBetween 1000 2100]
, prod = \tokens -> case tokens of
(token:_) -> do
n <- getIntValue token
tt $ year n
_ -> Nothing
}
I am new to Haskell. I was trying to modify the time parser in duckling.
I changed one of the several rules for parsing and received this error:
"lexical error in string/character literal at character 'd' " for line 4.
I am not sure what is the cause of this error and how to rectify it.