Produce multiple SOAP web services in Spring

Question

Here is a nice example on how to produce a SOAP web service in Spring: https://spring.io/guides/gs/producing-web-service/

This example shows, how to obtian one endpoint and one service. How to obtain the same result with multiple services and endpoints?

Create multiple modules one module (spring app for each web service you need) — StanislavL, Jun 26 '17 at 13:36
Hmm, in the end I need lots of endpoints and creating a module for each service seems like too much. Hope, there is a simpler way :) — JamesLinux, Jun 26 '17 at 14:02
https://stackoverflow.com/questions/18721604/how-to-define-separate-wsdl-for-different-services-in-a-same-spring-ws-project — StanislavL, Jun 26 '17 at 14:26
How to achieve the same result without config file? I'm using Spring tags in java only. — JamesLinux, Jun 27 '17 at 05:53

Mike Adamenko · Answer 1 · 2017-06-27T08:39:15.120

Basing on example from your link, all what you need to do is to add following methods to WebServiceConfig like:

@Bean(name = "webservice2")
public DefaultWsdl11Definition webservice2Wsdl11Definition(XsdSchema webservice2Schema) {
    DefaultWsdl11Definition wsdl11Definition = new DefaultWsdl11Definition();
    wsdl11Definition.setPortTypeName("webservice2Port");
    wsdl11Definition.setLocationUri("/ws");
    wsdl11Definition.setTargetNamespace("your namespace");
    wsdl11Definition.setSchema(webservice2Schema);
    return wsdl11Definition;
}

@Bean(name="webservice2Schema")
public XsdSchema webservice2Schema() {
    return new SimpleXsdSchema(new ClassPathResource("webservice2.xsd"));
}

And of course create

@Endpoint
public class Webservice2Endpoint

You can use as many webservices as you want in one module.

Add @Bean(name="webservice2Schema"). i 've updated the answer. — Mike Adamenko, Jun 27 '17 at 08:39

score 1 · Answer 2 · answered Jun 27 '17 at 06:24

Okay, it seems, that both answers were correct. I used Mike Adamenkos answer with a little extra tags to get it working.

@Bean(name = "webservice2")
public DefaultWsdl11Definition defaultWsdl11Definition(@Qualifier("Name") XsdSchema webservice2Schema) {
    DefaultWsdl11Definition wsdl11Definition = new DefaultWsdl11Definition();
    wsdl11Definition.setPortTypeName("webservice2Port");
    wsdl11Definition.setLocationUri("/ws");
    wsdl11Definition.setTargetNamespace("your namespace");
    wsdl11Definition.setSchema(webservice2Schema);
    return wsdl11Definition;
}

@Bean(name = "Name2")
public XsdSchema webservice2Schema() {
    return new SimpleXsdSchema(new ClassPathResource("webservice2.xsd"));
}

So you need to add a name value for the XsdSchema methods so you can get the correct method in your DefaultWsdl11Definition with the @Qualifier tag. Hope this helps!

For me it works without specific tags... BUT you only talk about the wsdl generation (it's what the defaultWsdl11Definition does). Here I have a servlet mapping issue: Having two (or more) WebServices suppose differents mappings. This means different MessageDispatcherServlet....But I can't make Spring deploy more than one servlet because MessageDispatcherServlet have all have the same name. — JN Gerbaux, Feb 05 '18 at 15:25

Produce multiple SOAP web services in Spring

2 Answers2